What is the solution for (dx)/(dt)=-40.8x+0.6 ?

The solution for (dx)/(dt)=-40.8x+0.6 is x=(e^{-40.79999…t-c_{1}})/(40.8)+(0.6)/(40.8)

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(dx)/(dt)=-40.8x+0.6

\frac{d x}{d t} = - 40.8 x + 0.6

x = \frac{e ^{- 40.79999 \dots t - c_{1}}}{40.8} + \frac{0.6}{40.8}

Solution steps

\frac{d x}{d t} = - 40.8 x + 0.6

Solve separable ODE:

x = \frac{e ^{- 40.79999 \dots t - c_{1}}}{40.8} + \frac{0.6}{40.8}

x = \frac{e ^{- 40.79999 \dots t - c_{1}}}{40.8} + \frac{0.6}{40.8}

x \to - \infty lim ((2)^{x})

x \to \infty lim (1, x)

\int_{0}^{4} x 21 - x^{2} d x

y^{^{''}} + 2 y^{^{'}} = 2 x + 5 - e^{- 2 x}

\frac{d}{d x} (1 - e^{- 5 x})

What is the solution for (dx)/(dt)=-40.8x+0.6 ?
The solution for (dx)/(dt)=-40.8x+0.6 is x=(e^{-40.79999…t-c_{1}})/(40.8)+(0.6)/(40.8)