What is the integral from 0 to 1 of 1/(sqrt(x)) ?

The integral from 0 to 1 of 1/(sqrt(x)) is 2

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integral from 0 to 1 of 1/(sqrt(x))

\int_{0}^{1} \frac{1}{x} d x

2

Solution steps

\int_{0}^{1} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{0}^{1}

= [2 x^{\frac{1}{2}}]_{0}^{1}

Apply radical rule:

= [2 x]_{0}^{1}

Compute the boundaries:

2

= 2

\int x cos (\frac{nπ x}{2}) d x

\frac{- u ^{2} + 3}{( u ^{2} + 3 ) ^{2}}

\int 2 cos (θ) cos^{5} (sin (θ)) d θ

n = 0 \sum \infty 4^{2 n}

x \to 1 lim (3 x^{3} - 5 x^{2} + x + 8)

What is the integral from 0 to 1 of 1/(sqrt(x)) ?
The integral from 0 to 1 of 1/(sqrt(x)) is 2