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Popular >

t^4y^{''}+t^3y^'=0

Solution

t^{4} y^{^{''}} + t^{3} y^{^{'}} = 0

Solution

y = c_{1} + c_{2} ln (t)

Solution steps

t^{4} y^{''} (t) + t^{3} y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} ln (t)

y = c_{1} + c_{2} ln (t)

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\int x^{4} e^{(x^{5} - 2)} d x

Frequently Asked Questions (FAQ)

What is the solution for t^4y^{''}+t^3y^'=0 ?
The solution for t^4y^{''}+t^3y^'=0 is y=c_{1}+c_{2}ln(t)