What is the solution for (dy)/(dx)+3xy^3=0 ?

The solution for (dy)/(dx)+3xy^3=0 is y=sqrt(-1/(-3x^2+c_{1))},y=-sqrt(-1/(-3x^2+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+3xy^3=0

\frac{d y}{d x} + 3 x y^{3} = 0

y = - \frac{1}{- 3 x ^{2} + c _{1}}, y = - - \frac{1}{- 3 x ^{2} + c _{1}}

Solution steps

\frac{d y}{d x} + 3 x y^{3} = 0

Solve separable ODE:

y = - \frac{1}{- 3 x ^{2} + c _{1}}, y = - - \frac{1}{- 3 x ^{2} + c _{1}}

y = - \frac{1}{- 3 x ^{2} + c _{1}}, y = - - \frac{1}{- 3 x ^{2} + c _{1}}

\int_{0}^{r} x arcsin (\frac{x}{2 r}) d x

\int \frac{sec ( x ) + cos ( x )}{8 cos ( x )} d x

\frac{\partial}{\partial x} (ln (x^{2} + 1))

x \to 1 + lim (arctan (ln (x)))

\frac{9 x}{3 x + 7}

What is the solution for (dy)/(dx)+3xy^3=0 ?
The solution for (dy)/(dx)+3xy^3=0 is y=sqrt(-1/(-3x^2+c_{1))},y=-sqrt(-1/(-3x^2+c_{1))}