What is the derivative of sin(tan(9x)) ?

The derivative of sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9

What is the first derivative of sin(tan(9x)) ?

The first derivative of sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9

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derivative of

sin (tan (9 x))

cos (tan (9 x)) sec^{2} (9 x) \cdot 9

Solution steps

\frac{d}{d x} (sin (tan (9 x)))

Apply the chain rule:

cos (tan (9 x)) \frac{d}{d x} (tan (9 x))

= cos (tan (9 x)) \frac{d}{d x} (tan (9 x))

\frac{d}{d x} (tan (9 x)) = sec^{2} (9 x) \cdot 9

= cos (tan (9 x)) sec^{2} (9 x) \cdot 9

\int \frac{1}{1 ^{2} + 2 x ^{2}} d x

\int \frac{x ^{3} - 5 x ^{2} + 3 x + 14}{x - 3} d x

f (x) = e^{- 3 x}, (0, 1)

\frac{d x}{d t} = 5 x (6 - x)

\frac{d y}{d x} + 3 y = 50

What is the derivative of sin(tan(9x)) ?
The derivative of sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9
What is the first derivative of sin(tan(9x)) ?
The first derivative of sin(tan(9x)) is cos(tan(9x))sec^2(9x)*9