What is the derivative of 2sin(5x) ?

The derivative of 2sin(5x) is 10cos(5x)

What is the first derivative of 2sin(5x) ?

The first derivative of 2sin(5x) is 10cos(5x)

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\frac{d}{d x} (2 sin (5 x))

10 cos (5 x)

Solution steps

\frac{d}{d x} (2 sin (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (5 x))

Apply the chain rule:

cos (5 x) \frac{d}{d x} (5 x)

= cos (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 2 cos (5 x) \cdot 5

Simplify

= 10 cos (5 x)

x \to 0 + lim (8 x ln (x))

F (t) = (3 t - 1)^{4} (2 t + 1)^{- 3}

t y^{^{'}} + y = t^{4} y^{3}

\int (a x^{2} + b x + c) d x

y = \frac{2 x - 1}{x + 2}

What is the derivative of 2sin(5x) ?
The derivative of 2sin(5x) is 10cos(5x)
What is the first derivative of 2sin(5x) ?
The first derivative of 2sin(5x) is 10cos(5x)