What is the derivative of e^{x-1}-x+1 ?

The derivative of e^{x-1}-x+1 is e^{x-1}-1

What is the first derivative of e^{x-1}-x+1 ?

The first derivative of e^{x-1}-x+1 is e^{x-1}-1

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\frac{d}{d x} (e^{x - 1} - x + 1)

e^{x - 1} - 1

Solution steps

\frac{d}{d x} (e^{x - 1} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x - 1}) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (e^{x - 1}) = e^{x - 1}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= e^{x - 1} - 1 + 0

Simplify

= e^{x - 1} - 1

f (x) = x^{8} e^{x}

x y^{^{'}} + y = e^{x}, y (1) = 5

\int_{1}^{5} 26 d x

x^{2} e^{x}

y = 4 x, y = x

What is the derivative of e^{x-1}-x+1 ?
The derivative of e^{x-1}-x+1 is e^{x-1}-1
What is the first derivative of e^{x-1}-x+1 ?
The first derivative of e^{x-1}-x+1 is e^{x-1}-1