What is the solution for y^'+y=e^xy^{-2} ?

The solution for y^'+y=e^xy^{-2} is y=\sqrt[3]{(3e^{4x}+c_{1})/(4e^{3x)}}

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y^'+y=e^xy^{-2}

y^{^{'}} + y = e^{x} y^{- 2}

Solution steps

y^{'} (x) + y = e^{x} y^{- 2}

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What is the solution for y^'+y=e^xy^{-2} ?
The solution for y^'+y=e^xy^{-2} is y=\sqrt[3]{(3e^{4x}+c_{1})/(4e^{3x)}}