What is area x^2+5x+1,x^3+x^2+x+1 ?

The answer to area x^2+5x+1,x^3+x^2+x+1 is 8

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area x^2+5x+1,x^3+x^2+x+1

area

x^{2} + 5 x + 1, x^{3} + x^{2} + x + 1

8

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} + 5 x + 1 - (x^{3} + x^{2} + x + 1) d x

Solve

\int_{- 2}^{2} x^{2} + 5 x + 1 - (x^{3} + x^{2} + x + 1) d x : 8

The area is:

= 8

\int \frac{1}{( x - 2 ) ^{3}} d x

\int x^{3} (x^{4} + 16)^{4} d x

\frac{d}{d x} (- cot (x) csc (x))

x \to 5 lim (2 x^{2} - 3 x + 7)

f (x) = 1 + cos (x)

What is area x^2+5x+1,x^3+x^2+x+1 ?
The answer to area x^2+5x+1,x^3+x^2+x+1 is 8