What is the solution for (xdx+ydy)/((x^2+y^2)^{3/2)}=0 ?

The solution for (xdx+ydy)/((x^2+y^2)^{3/2)}=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(xdx+ydy)/((x^2+y^2)^{3/2)}=0

\frac{x d x + y d y}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

\frac{x d x + y d y}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}} = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\frac{d ^{2}}{d x ^{2}} (\frac{8}{9 t ^{4}})

\frac{\partial}{\partial x} (x^{2} + \frac{x}{t} + sin (x))

\frac{d y}{d x} = 18 x^{5} e^{3 x^{6}}

\int (sin (x y)) d y

\frac{d ^{2} x}{d t ^{2}} + 6 \frac{d x}{d t} + 8 x = 5 sin (3 t)

What is the solution for (xdx+ydy)/((x^2+y^2)^{3/2)}=0 ?
The solution for (xdx+ydy)/((x^2+y^2)^{3/2)}=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}