What is (d^2)/(dx^2)(x^{9/2}e^x) ?

The answer to (d^2)/(dx^2)(x^{9/2}e^x) is (36e^xx^{7/2}+63e^xx^{5/2}+4e^xx^{9/2})/4

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(d^2)/(dx^2)(x^{9/2}e^x)

\frac{d ^{2}}{d x ^{2}} (x^{\frac{9}{2}} e^{x})

\frac{36 e ^{x} x ^{\frac{7}{2}} + 63 e ^{x} x ^{\frac{5}{2}} + 4 e ^{x} x ^{\frac{9}{2}}}{4}

Solution steps

\frac{d ^{2}}{d x ^{2}} (x^{\frac{9}{2}} e^{x})

\frac{d}{d x} (x^{\frac{9}{2}} e^{x}) = \frac{9 e ^{x} x ^{\frac{7}{2}}}{2} + e^{x} x^{\frac{9}{2}}

= \frac{d}{d x} (\frac{9 e ^{x} x ^{\frac{7}{2}}}{2} + e^{x} x^{\frac{9}{2}})

\frac{d}{d x} (\frac{9 e ^{x} x ^{\frac{7}{2}}}{2} + e^{x} x^{\frac{9}{2}}) = \frac{36 e ^{x} x ^{\frac{7}{2}} + 63 e ^{x} x ^{\frac{5}{2}} + 4 e ^{x} x ^{\frac{9}{2}}}{4}

= \frac{36 e ^{x} x ^{\frac{7}{2}} + 63 e ^{x} x ^{\frac{5}{2}} + 4 e ^{x} x ^{\frac{9}{2}}}{4}

x \to \infty lim (- 2 (x))

n = 1 \sum \infty \frac{9 n}{10}

(- 10, - 3), (4, - 3)

\int e^{9 x - 14} d x

g (x) = e^{3}

What is (d^2)/(dx^2)(x^{9/2}e^x) ?
The answer to (d^2)/(dx^2)(x^{9/2}e^x) is (36e^xx^{7/2}+63e^xx^{5/2}+4e^xx^{9/2})/4