What is derivative of f(x)=4t^{-3/8} ?

The answer to derivative of f(x)=4t^{-3/8} is (dt)/(dx)=0

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derivative of f(x)=4t^{-3/8}

derivative of

f (x) = 4 t^{- \frac{3}{8}}

\frac{d t}{d x} = 0

Solution steps

f (x) = 4 t^{- \frac{3}{8}}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{3 \frac{d t}{d x}}{2 t ^{\frac{11}{8}}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{x ^{6}}{1 - x ^{5}}

\int sin (2 t) + cos (t) d t

\int (1 + 4 x^{2}) d x

\frac{d}{d x} (\frac{11}{ln ( x )})

x \frac{d y}{d x} + y = sin (x)

What is derivative of f(x)=4t^{-3/8} ?
The answer to derivative of f(x)=4t^{-3/8} is (dt)/(dx)=0