What is the tangent of f(x)=2x^2-6x+6,\at x=7 ?

The tangent of f(x)=2x^2-6x+6,\at x=7 is y=22x-92

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2-6x+6,\at x=7

tangent of

f (x) = 2 x^{2} - 6 x + 6, at x = 7

y = 22 x - 92

Solution steps

Find the tangent point:

(7, 62)

Find the slope of

f (x) = 2 x^{2} - 6 x + 6 : \frac{df ( x )}{d x} = 4 x - 6

Compute the slope of

f (x) = 2 x^{2} - 6 x + 6

x = 7 : m = 22

Find the line with slope m=

22

and passing through

(7, 62) : y = 22 x - 92

y = 22 x - 92

\frac{\partial}{\partial x} (x \cdot y \cdot ln (x^{2} + y^{2}))

ln (1 + e^{x})

\frac{5 x}{x + 4}

\frac{d}{d x} (\frac{3}{tan ( x )})

What is the tangent of f(x)=2x^2-6x+6,\at x=7 ?
The tangent of f(x)=2x^2-6x+6,\at x=7 is y=22x-92