What is (\partial)/(\partial x)(2x^2y-x^3) ?

The answer to (\partial)/(\partial x)(2x^2y-x^3) is 4yx-3x^2

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(\partial)/(\partial x)(2x^2y-x^3)

\frac{\partial}{\partial x} (2 x^{2} y - x^{3})

4 y x - 3 x^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{2} y - x^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2} y) - \frac{\partial}{\partial x} (x^{3})

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

= 4 y x - 3 x^{2}

n = 1 \sum \infty \frac{2}{3 ^{n + 1}}

\frac{1}{S}

\int \frac{( 4 - 2 x )}{( x + 1 ) ( x - 1 ) ^{2}} d x

\int_{1}^{\infty} \frac{3}{x ^{2}} d x

x \to - 4 lim (x^{2} - 8)

What is (\partial)/(\partial x)(2x^2y-x^3) ?
The answer to (\partial)/(\partial x)(2x^2y-x^3) is 4yx-3x^2