What is the integral of 1/((3x+5)^3) ?

The integral of 1/((3x+5)^3) is -1/(6(3x+5)^2)+C

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integral of 1/((3x+5)^3)

\int \frac{1}{( 3 x + 5 ) ^{3}} d x

- \frac{1}{6 ( 3 x + 5 ) ^{2}} + C

Solution steps

\int \frac{1}{( 3 x + 5 ) ^{3}} d x

Apply u-substitution

: \int \frac{1}{3 u ^{3}} d u

= \int \frac{1}{3 u ^{3}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1}{u ^{3}} d u

Apply the Power Rule

: - \frac{1}{2 u ^{2}}

= \frac{1}{3} (- \frac{1}{2 u ^{2}})

Substitute back

u = 3 x + 5

= \frac{1}{3} (- \frac{1}{2 ( 3 x + 5 ) ^{2}})

Simplify

\frac{1}{3} (- \frac{1}{2 ( 3 x + 5 ) ^{2}}) : - \frac{1}{6 ( 3 x + 5 ) ^{2}}

= - \frac{1}{6 ( 3 x + 5 ) ^{2}}

Add a constant to the solution

= - \frac{1}{6 ( 3 x + 5 ) ^{2}} + C

f (x) = 2 x^{3} - 9 x^{2} + 12 x - 6

\frac{d y}{d t} = k (y - 20)

\frac{( 1 - e ^{- 3 s} )}{s}

\frac{d}{d x} (csc^{4} (2 x))

\int \frac{y ^{n - 1}}{( a y ^{n} + b ) ^{m}} d y

What is the integral of 1/((3x+5)^3) ?
The integral of 1/((3x+5)^3) is -1/(6(3x+5)^2)+C