What is the solution for x(dy)/(dx)+6y=1-4/x ?

The solution for x(dy)/(dx)+6y=1-4/x is y= 1/6-4/(5x)+(c_{1})/(x^6)

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x(dy)/(dx)+6y=1-4/x

x \frac{d y}{d x} + 6 y = 1 - \frac{4}{x}

y = \frac{1}{6} - \frac{4}{5 x} + \frac{c _{1}}{x ^{6}}

Solution steps

x \frac{d y}{d x} + 6 y = 1 - \frac{4}{x}

Solve linear ODE:

y = \frac{1}{6} - \frac{4}{5 x} + \frac{c _{1}}{x ^{6}}

y = \frac{1}{6} - \frac{4}{5 x} + \frac{c _{1}}{x ^{6}}

\int sec^{7} (2 x) tan (2 x) d x

\int \frac{( x + 1 ) ^{4}}{( x ^{2} + 2 x + 2 ) ^{3}} d x

\int x cos^{3} (x^{2}) d x

\frac{d}{d x} ((1 + 5 x^{2}) (x - x^{2}))

\frac{8}{x ^{2}}

What is the solution for x(dy)/(dx)+6y=1-4/x ?
The solution for x(dy)/(dx)+6y=1-4/x is y= 1/6-4/(5x)+(c_{1})/(x^6)