What is the first (sin(2θ))^' ?

The first (sin(2θ))^' is cos(2θ)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sin(2θ))^'

(sin (2 θ))^{^{'}}

cos (2 θ) \cdot 2

Solution steps

(sin (2 θ))^{'}

Apply the chain rule:

cos (2 θ) (2 θ)^{'}

= cos (2 θ) (2 θ)^{'}

(2 θ)^{'} = 2

= cos (2 θ) \cdot 2

h \to 0 lim (\frac{sin ( h )}{7 h})

y \to 0 lim (\frac{5}{y ^{2} + y} - \frac{5}{y})

\int_{3}^{\infty} \frac{1}{x ^{2} - 1} d x

\int 4 \frac{sin ( 2 x )}{sin ( x )} d x

\frac{s - 6}{s + 2}