What is the integral from 0 to 5 of x^3 ?

The integral from 0 to 5 of x^3 is 625/4

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integral from 0 to 5 of x^3

\int_{0}^{5} x^{3} d x

\frac{625}{4}

Decimal Notation

156.25

Solution steps

\int_{0}^{5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{5}

= [\frac{x ^{4}}{4}]_{0}^{5}

Compute the boundaries:

\frac{625}{4}

= \frac{625}{4}

y^{^{''}} x^{2} - 5 x y^{^{'}} + 9 y = 0

cos^{2} (k t)

\int_{0}^{3} 3 d x

\frac{d}{d x} (\frac{x - ln ( 1 + x )}{x ^{2}})

\int x ln (3) d x

What is the integral from 0 to 5 of x^3 ?
The integral from 0 to 5 of x^3 is 625/4