What is the sum from n=2 to infinity of e^{3-2n} ?

The sum from n=2 to infinity of e^{3-2n} is converges

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sum from n=2 to infinity of e^{3-2n}

n = 2 \sum \infty e^{3 - 2 n}

converges

Solution steps

n = 2 \sum \infty e^{3 - 2 n}

Apply Series Ratio Test:

converges

= converges

\int 3 (3 x + 9)^{3} d x

x \to 0 lim (\frac{sinh ( x ) - x}{x ^{3}})

e^{n \cdot x}

\frac{x ^{2}}{4}, \frac{- x + 6}{4}, - 3, 2

\frac{10 x + 2 x ^{2}}{( 5 + 2 x ) ^{2}}

What is the sum from n=2 to infinity of e^{3-2n} ?
The sum from n=2 to infinity of e^{3-2n} is converges