What is the derivative of 4xe^x ?

The derivative of 4xe^x is 4(e^x+e^xx)

What is the first derivative of 4xe^x ?

The first derivative of 4xe^x is 4(e^x+e^xx)

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derivative of

4 x e^{x}

4 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (4 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 4 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 4 (1 \cdot e^{x} + e^{x} x)

Simplify

= 4 (e^{x} + e^{x} x)

\frac{\partial}{\partial y} (4 x^{2} + y^{2} - 800)

f (x) = x^{3} - 8 x^{2}, at x = 0

\int sec^{6} (x) tan^{5} (x) d x

x \to 0 lim (\frac{x ^{2}}{2})

\frac{d}{d x} (\frac{( x ^{2} + 3 x - 4 )}{x + 2})

What is the derivative of 4xe^x ?
The derivative of 4xe^x is 4(e^x+e^xx)
What is the first derivative of 4xe^x ?
The first derivative of 4xe^x is 4(e^x+e^xx)