en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'+y=3xy^2,y(1)=-3

Solution

x y^{^{'}} + y = 3 x y^{2}, y (1) = - 3

Solution

y = - \frac{3}{x ( 9 ln ( x ) + 1 )}

Solution steps

x y^{'} (x) + y = 3 x y^{2}

Solve Bernoulli ODE:

y = - \frac{3}{x ( 9 ln ( x ) + 1 )}

y = - \frac{3}{x ( 9 ln ( x ) + 1 )}

Popular Examples

derivative of sqrt(7x)derivative of

7 x

(\partial)/(\partial y)(-4x^3y)

\frac{\partial}{\partial y} (- 4 x^{3} y)

derivative of 3dx

\frac{d}{d x} (3 d x)

(\partial)/(\partial z)(ln((xy)/(y^2+z^2)))

\frac{\partial}{\partial z} (ln (\frac{x y}{y ^{2} + z ^{2}}))

area y^2=x,y=x-2 area

y^{2} = x, y = x - 2

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=3xy^2,y(1)=-3 ?
The solution for xy^'+y=3xy^2,y(1)=-3 is y=-3/(x(9ln(x)+1))