What is the integral from 0 to pi/6 of sec(x) ?

The integral from 0 to pi/6 of sec(x) is 1/2 ln(3)

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integral from 0 to pi/6 of sec(x)

\int_{0}^{\frac{π}{6}} sec (x) d x

\frac{1}{2} ln (3)

Decimal Notation

0.54930 \dots

Solution steps

\int_{0}^{\frac{π}{6}} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= [ln ∣ tan (x) + sec (x) ∣]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{2} ln (3)

= \frac{1}{2} ln (3)

x \to - 1 lim (\frac{1}{- x - 1})

\int (2 x^{2} - 4 x)^{9} (x - 1) d x

\int 8 x^{3} + 30 x - 1 d x

\frac{d}{d x} (\frac{x ^{3} - y ^{3}}{x ^{2} + y ^{2}})

\frac{\partial}{\partial x} (cos^{4} (x^{8} y^{7}))

What is the integral from 0 to pi/6 of sec(x) ?
The integral from 0 to pi/6 of sec(x) is 1/2 ln(3)