What is the sum from n=0 to infinity of 1/(n^3) ?

The sum from n=0 to infinity of 1/(n^3) is converges

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sum from n=0 to infinity of 1/(n^3)

n = 0 \sum \infty \frac{1}{n ^{3}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{3}}

Apply p-Series Test:

converges

= converges

\frac{d}{d x} (\frac{4}{x - 1})

\int (x - 1)^{2} x d x

\frac{64}{( 1 + 4 x ) ^{3}}

(x + 1) \frac{d y}{d x} - x y = x + x^{2}

x \to 9 lim (8 x + ∣ x - 9 ∣)

What is the sum from n=0 to infinity of 1/(n^3) ?
The sum from n=0 to infinity of 1/(n^3) is converges