What is the derivative of 4x^{5/4}+8x^{3/2}+3x ?

The derivative of 4x^{5/4}+8x^{3/2}+3x is 5x^{1/4}+12x^{1/2}+3

What is the first derivative of 4x^{5/4}+8x^{3/2}+3x ?

The first derivative of 4x^{5/4}+8x^{3/2}+3x is 5x^{1/4}+12x^{1/2}+3

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derivative of

4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 3 x

5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 3

Solution steps

\frac{d}{d x} (4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{5}{4}}) + \frac{d}{d x} (8 x^{\frac{3}{2}}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{\frac{5}{4}}) = 5 x^{\frac{1}{4}}

\frac{d}{d x} (8 x^{\frac{3}{2}}) = 12 x^{\frac{1}{2}}

\frac{d}{d x} (3 x) = 3

= 5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 3

y^{^{'}} = \frac{( y - y ^{2} )}{x}

\frac{1 + x}{1 - x} - 1

f (x) = sec (x^{2})

\frac{d}{d x} (9 + 3 x + sin (3 x))

f (x) = 2 x^{- 1}, at x = 5

What is the derivative of 4x^{5/4}+8x^{3/2}+3x ?
The derivative of 4x^{5/4}+8x^{3/2}+3x is 5x^{1/4}+12x^{1/2}+3
What is the first derivative of 4x^{5/4}+8x^{3/2}+3x ?
The first derivative of 4x^{5/4}+8x^{3/2}+3x is 5x^{1/4}+12x^{1/2}+3