What is the integral from-3 to 0 of (2+sqrt(9-x^2)) ?

The integral from-3 to 0 of (2+sqrt(9-x^2)) is 6+(9pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 0 of (2+sqrt(9-x^2))

\int_{- 3}^{0} (2 + 9 - x^{2}) d x

6 + \frac{9 π}{4}

Decimal Notation

13.06858 \dots

Solution steps

\int_{- 3}^{0} 2 + 9 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{0} 2 d x + \int_{- 3}^{0} 9 - x^{2} d x

\int_{- 3}^{0} 2 d x = 6

\int_{- 3}^{0} 9 - x^{2} d x = \frac{9 π}{4}

= 6 + \frac{9 π}{4}

n = 0 \sum \infty n e^{- 2 n}

x \to \infty lim (- \frac{10}{x})

y^{^{''}} + 16 y = - 32 sin (4 x)

f (x) = 9 x - x^{2}, (1, 8)

\frac{s + 3}{s ( s + 2 )}

What is the integral from-3 to 0 of (2+sqrt(9-x^2)) ?
The integral from-3 to 0 of (2+sqrt(9-x^2)) is 6+(9pi)/4