What is (\partial)/(\partial x)(6x+y^2) ?

The answer to (\partial)/(\partial x)(6x+y^2) is 6

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(\partial)/(\partial x)(6x+y^2)

\frac{\partial}{\partial x} (6 x + y^{2})

6

Solution steps

\frac{\partial}{\partial x} (6 x + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 x) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (6 x) = 6

\frac{\partial}{\partial x} (y^{2}) = 0

= 6 + 0

Simplify

= 6

n = 1 \sum \infty \frac{6 n !}{n ^{n}}

\frac{d}{d x} (\frac{x ^{2} - 5}{1 - 3 x ^{2}})

6 (sin (x^{2}) + 2 x^{2} cos (x^{2}))

\frac{d}{d x} (\frac{x ^{2} tan ( x ^{3} - x ^{2} )}{sec ( x )})

y^{^{''}} + 3 y^{^{'}} = 10 sin (t)

What is (\partial)/(\partial x)(6x+y^2) ?
The answer to (\partial)/(\partial x)(6x+y^2) is 6