What is (\partial)/(\partial x)(7xe^x) ?

The answer to (\partial)/(\partial x)(7xe^x) is 7(e^x+e^xx)

Popular >

(\partial)/(\partial x)(7xe^x)

\frac{\partial}{\partial x} (7 x e^{x})

7 (e^{x} + e^{x} x)

Solution steps

\frac{\partial}{\partial x} (7 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 7 (\frac{\partial}{\partial x} (x) e^{x} + \frac{\partial}{\partial x} (e^{x}) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 7 (1 \cdot e^{x} + e^{x} x)

Simplify

= 7 (e^{x} + e^{x} x)

\frac{1}{( s ^{2} ( 1 + s ) )}

\frac{d}{d x} ((x^{2}) - 2 x - 10)

\int_{0}^{π} u sin^{2} (u) d u

(1 + x^{4}) d y + (1 + 4 y^{2}) d x = 0

y^{^{'}} - 5 y^{(2)} e^{(- 3 x)} = 0, y (0) = 9

What is (\partial)/(\partial x)(7xe^x) ?
The answer to (\partial)/(\partial x)(7xe^x) is 7(e^x+e^xx)