What is the derivative of (3\sqrt[3]{2}x^{5/3}/5) ?

The derivative of (3\sqrt[3]{2}x^{5/3}/5) is cube root of 2}x^{2/3

What is the first derivative of (3\sqrt[3]{2}x^{5/3}/5) ?

The first derivative of (3\sqrt[3]{2}x^{5/3}/5) is cube root of 2}x^{2/3

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Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

Simplify

7 x, \frac{7}{4} x, 78 - x^{2}, y = 0

y^{^{''}} + 2 \cdot y^{^{'}} + 26 \cdot y = e^{- x} cos (5 \cdot x)

\int \frac{8000 - 2000 x}{( x ^{2} - 8 x + 17 ) ^{2}} d x

\frac{d}{d x} (x^{5} \cdot tan (x))

n = 1 \sum \infty 1

What is the derivative of (3\sqrt[3]{2}x^{5/3}/5) ?
The derivative of (3\sqrt[3]{2}x^{5/3}/5) is cube root of 2}x^{2/3
What is the first derivative of (3\sqrt[3]{2}x^{5/3}/5) ?
The first derivative of (3\sqrt[3]{2}x^{5/3}/5) is cube root of 2}x^{2/3