What is the derivative of x^2*2x ?

The derivative of x^2*2x is 6x^2

What is the first derivative of x^2*2x ?

The first derivative of x^2*2x is 6x^2

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\frac{d}{d x} (x^{2} \cdot 2 x)

6 x^{2}

Solution steps

\frac{d}{d x} (x^{2} \cdot 2 x)

Simplify

x^{2} \cdot 2 x : 2 x^{3}

= \frac{d}{d x} (2 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 x^{3 - 1}

Simplify

= 6 x^{2}

\frac{d}{d x} (x^{2} ln (\frac{x}{2}))

x \to \frac{2}{3} lim (\frac{3 x - 2}{3 x ^{2} - 11 x + 6})

\frac{\partial}{\partial z} (x y + yz + z x)

\frac{d}{d x} (x cos^{3} (x))

\int_{1}^{2} x ln (x) d x