What is the tangent of x^{2/3}+y^{2/3}=5,(1,8) ?

The tangent of x^{2/3}+y^{2/3}=5,(1,8) is y=-2x+10

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tangent of x^{2/3}+y^{2/3}=5,(1,8)

tangent of

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 5, (1, 8)

y = - 2 x + 10

Solution steps

Find the slope of

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 5 : \frac{d y}{d x} = - (\frac{y}{x})^{\frac{1}{3}}

Compute the slope of

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 5

(1, 8) : m = - 2

Find the line with slope m=

- 2

and passing through

(1, 8) : y = - 2 x + 10

y = - 2 x + 10

f (x) = \frac{2 x - 1}{2 x + 1}

t e^{- t}

\int (x + 3) e^{x^{2} + 6 x} d x

x \to 1 + lim (\frac{x - 1}{∣ x - 1 ∣})

2 sec (x) tan (x)

What is the tangent of x^{2/3}+y^{2/3}=5,(1,8) ?
The tangent of x^{2/3}+y^{2/3}=5,(1,8) is y=-2x+10