What is the tangent of f(x)=(x-8)/(3x-4),\at x=2 ?

The tangent of f(x)=(x-8)/(3x-4),\at x=2 is y=5x-13

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tangent of f(x)=(x-8)/(3x-4),\at x=2

tangent of

f (x) = \frac{x - 8}{3 x - 4}, at x = 2

y = 5 x - 13

Solution steps

Find the tangent point:

(2, - 3)

Find the slope of

f (x) = \frac{x - 8}{3 x - 4} : \frac{df ( x )}{d x} = \frac{20}{( 3 x - 4 ) ^{2}}

Compute the slope of

f (x) = \frac{x - 8}{3 x - 4}

x = 2 : m = 5

Find the line with slope m=

5

and passing through

(2, - 3) : y = 5 x - 13

y = 5 x - 13

\frac{d}{d x} (cos (x z (x)))

\int x^{\frac{4}{3}} - 3 x^{\frac{5}{2}} d x

\int \frac{x ^{3}}{x + 1} d x

\int_{0}^{2} 4 - x^{2} d x

\frac{d}{d t} (1 + 2 t)

What is the tangent of f(x)=(x-8)/(3x-4),\at x=2 ?
The tangent of f(x)=(x-8)/(3x-4),\at x=2 is y=5x-13