What is the derivative of (x+9/(x^3+x-8)) ?

The derivative of (x+9/(x^3+x-8)) is (-2x^3-27x^2-17)/((x^3+x-8)^2)

What is the first derivative of (x+9/(x^3+x-8)) ?

The first derivative of (x+9/(x^3+x-8)) is (-2x^3-27x^2-17)/((x^3+x-8)^2)

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\frac{d}{d x} (\frac{x + 9}{x ^{3} + x - 8})

\frac{- 2 x ^{3} - 27 x ^{2} - 17}{( x ^{3} + x - 8 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 9}{x ^{3} + x - 8})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 9 ) ( x ^{3} + x - 8 ) - \frac{d}{d x} ( x ^{3} + x - 8 ) ( x + 9 )}{( x ^{3} + x - 8 ) ^{2}}

\frac{d}{d x} (x + 9) = 1

\frac{d}{d x} (x^{3} + x - 8) = 3 x^{2} + 1

= \frac{1 \cdot ( x ^{3} + x - 8 ) - ( 3 x ^{2} + 1 ) ( x + 9 )}{( x ^{3} + x - 8 ) ^{2}}

Simplify

\frac{1 \cdot ( x ^{3} + x - 8 ) - ( 3 x ^{2} + 1 ) ( x + 9 )}{( x ^{3} + x - 8 ) ^{2}} : \frac{- 2 x ^{3} - 27 x ^{2} - 17}{( x ^{3} + x - 8 ) ^{2}}

= \frac{- 2 x ^{3} - 27 x ^{2} - 17}{( x ^{3} + x - 8 ) ^{2}}

\int_{- 1}^{3} \frac{x}{x ^{2} + 1} d x

- 6 cos (t)

y = 2 x^{3}, (- 2, - 16)

\int_{1}^{- 1} (12 x + 11)^{2} d x

\frac{d}{d x} (arcsin (x ln (x)))

What is the derivative of (x+9/(x^3+x-8)) ?
The derivative of (x+9/(x^3+x-8)) is (-2x^3-27x^2-17)/((x^3+x-8)^2)
What is the first derivative of (x+9/(x^3+x-8)) ?
The first derivative of (x+9/(x^3+x-8)) is (-2x^3-27x^2-17)/((x^3+x-8)^2)