What is the solution for y^{''}+12y^'+37y=0 ?

The solution for y^{''}+12y^'+37y=0 is y=e^{-6t}(c_{1}cos(t)+c_{2}sin(t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+12y^'+37y=0

y^{^{''}} + 12 y^{^{'}} + 37 y = 0

y = e^{- 6 t} (c_{1} cos (t) + c_{2} sin (t))

Solution steps

y^{''} (t) + 12 y^{'} (t) + 37 y = 0

Solve linear ODE:

y = e^{- 6 t} (c_{1} cos (t) + c_{2} sin (t))

y = e^{- 6 t} (c_{1} cos (t) + c_{2} sin (t))

x \to - 5 - lim (\frac{- 2}{x ^{2} - 25})

\int \frac{8}{64 - x ^{2}} d x

\frac{18 x + 4 x ^{2}}{( 9 + 4 x ) ^{2}}

\int e^{- x} cos (a x) d x

\int 2 x e^{- y} d x

What is the solution for y^{''}+12y^'+37y=0 ?
The solution for y^{''}+12y^'+37y=0 is y=e^{-6t}(c_{1}cos(t)+c_{2}sin(t))