What is the tangent of f(x)= 2/(x+1),(4, 2/5) ?

The tangent of f(x)= 2/(x+1),(4, 2/5) is y=-2/25 x+18/25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 2/(x+1),(4, 2/5)

tangent of

f (x) = \frac{2}{x + 1}, (4, \frac{2}{5})

y = - \frac{2}{25} x + \frac{18}{25}

Solution steps

Find the slope of

f (x) = \frac{2}{x + 1} : \frac{df ( x )}{d x} = - \frac{2}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{x + 1}

(4, \frac{2}{5}) : m = - \frac{2}{25}

Find the line with slope m=

- \frac{2}{25}

and passing through

(4, \frac{2}{5}) : y = - \frac{2}{25} x + \frac{18}{25}

y = - \frac{2}{25} x + \frac{18}{25}

2 \cdot e^{3 x}

\frac{d}{d x} (3 cos (x) - 2 sin (x))

\frac{\partial}{\partial x} (x - y - 2)

\int (cot^{2} (x)) d x

\int 7 x^{2} (6 x^{3} + 3)^{3} d x

What is the tangent of f(x)= 2/(x+1),(4, 2/5) ?
The tangent of f(x)= 2/(x+1),(4, 2/5) is y=-2/25 x+18/25