What is the solution for y^'+((3y)/((300-t)))=4 ?

The solution for y^'+((3y)/((300-t)))=4 is y=-2(t-300)+c_{1}(27000000-270000t+900t^2-t^3)

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y^'+((3y)/((300-t)))=4

y^{^{'}} + (\frac{3 y}{( 300 - t )}) = 4

y = - 2 (t - 300) + c_{1} (27000000 - 270000 t + 900 t^{2} - t^{3})

Solution steps

y^{'} (t) + (\frac{3 y}{( 300 - t )}) = 4

Solve linear ODE:

y = - 2 (t - 300) + c_{1} (27000000 - 270000 t + 900 t^{2} - t^{3})

y = - 2 (t - 300) + c_{1} (27000000 - 270000 t + 900 t^{2} - t^{3})

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What is the solution for y^'+((3y)/((300-t)))=4 ?
The solution for y^'+((3y)/((300-t)))=4 is y=-2(t-300)+c_{1}(27000000-270000t+900t^2-t^3)