What is the tangent of f(x)=4cos(x),(pi/3 ,2) ?

The tangent of f(x)=4cos(x),(pi/3 ,2) is y=-2sqrt(3)x+2+(2pi)/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=4cos(x),(pi/3 ,2)

tangent of

f (x) = 4 cos (x), (\frac{π}{3}, 2)

y = - 23 x + 2 + \frac{2 π}{3}

Solution steps

Find the slope of

f (x) = 4 cos (x) : \frac{df ( x )}{d x} = - 4 sin (x)

Compute the slope of

f (x) = 4 cos (x)

(\frac{π}{3}, 2) : m = - 23

Find the line with slope m=

- 23

and passing through

(\frac{π}{3}, 2) : y = - 23 x + 2 + \frac{2 π}{3}

y = - 23 x + 2 + \frac{2 π}{3}

\frac{\partial}{\partial w} (t e^{\frac{w}{t}})

\int \frac{x e ^{3 x}}{2} d x

\int_{k}^{2 k} \frac{2}{( 2 x - k ) ^{2}} d x

\int \frac{sec ( x )}{sec ( x ) - cos ( x )} d x

\frac{d}{d x} (- 18)

What is the tangent of f(x)=4cos(x),(pi/3 ,2) ?
The tangent of f(x)=4cos(x),(pi/3 ,2) is y=-2sqrt(3)x+2+(2pi)/(sqrt(3))