What is the limit as x approaches 2 of ln(x^2-4) ?

The limit as x approaches 2 of ln(x^2-4) is Does not exist

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limit as x approaches 2 of ln(x^2-4)

x \to 2 lim (ln (x^{2} - 4))

Does not exist

Solution steps

x \to 2 lim (ln (x^{2} - 4))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (ln (x^{2} - 4)) = - \infty

x \to 2 - lim (ln (x^{2} - 4)) =

Does not exist

= Does not exist

\frac{d}{d x} (\frac{e ^{x}}{x \cdot cos ( x )})

f^{^{''}} + 16 f = sin (2 x)

\int_{6}^{12} 144 - x^{2} d x

x^{2} y^{^{''}} - 6 y = 0, y (1) = 6, y^{^{'}} (1) = - 2

\frac{\partial}{\partial x} (e^{x y} y^{2} + \frac{x}{y})

What is the limit as x approaches 2 of ln(x^2-4) ?
The limit as x approaches 2 of ln(x^2-4) is Does not exist