What is the derivative of y= 1/((3x+8)^2) ?

The derivative of y= 1/((3x+8)^2) is -6/((3x+8)^3)

What is the first derivative of y= 1/((3x+8)^2) ?

The first derivative of y= 1/((3x+8)^2) is -6/((3x+8)^3)

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derivative of

y = \frac{1}{( 3 x + 8 ) ^{2}}

- \frac{6}{( 3 x + 8 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( 3 x + 8 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 x + 8)^{- 2})

Apply the chain rule:

- \frac{2}{( 3 x + 8 ) ^{3}} \frac{d}{d x} (3 x + 8)

= - \frac{2}{( 3 x + 8 ) ^{3}} \frac{d}{d x} (3 x + 8)

\frac{d}{d x} (3 x + 8) = 3

= - \frac{2}{( 3 x + 8 ) ^{3}} \cdot 3

Simplify

- \frac{2}{( 3 x + 8 ) ^{3}} \cdot 3 : - \frac{6}{( 3 x + 8 ) ^{3}}

= - \frac{6}{( 3 x + 8 ) ^{3}}

x \to - 3 lim (5 x)

- 2 9 s^{2} + 1

x \to 2 - lim (f (x))

\frac{d}{d x} ((x^{2} 7^{x})^{9})

\frac{d}{d x} (e^{x^{2} + x})

What is the derivative of y= 1/((3x+8)^2) ?
The derivative of y= 1/((3x+8)^2) is -6/((3x+8)^3)
What is the first derivative of y= 1/((3x+8)^2) ?
The first derivative of y= 1/((3x+8)^2) is -6/((3x+8)^3)