What is the solution for (dy)/(sqrt(1-y^2))=dx ?

The solution for (dy)/(sqrt(1-y^2))=dx is y=sin(x+c_{1})

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(dy)/(sqrt(1-y^2))=dx

\frac{d y}{1 - y ^{2}} = d x

y = sin (x + c_{1})

Solution steps

\frac{d y}{1 - y ^{2}} = d x

Solve separable ODE:

y = sin (x + c_{1})

y = sin (x + c_{1})

\frac{d y}{d t} = \frac{8 t y}{t ^{2} + 1}, y (0) = - 2

\int 15 x^{2} d x

\int sec^{2} (3 x) e^{t a n (3 x) - 2} d x

\int \frac{1}{4 + u ^{2}} d u

x y^{^{'}} + y = e^{x}, y (1) = 2

What is the solution for (dy)/(sqrt(1-y^2))=dx ?
The solution for (dy)/(sqrt(1-y^2))=dx is y=sin(x+c_{1})