What is laplacetransform e^{-t}*sin(t) ?

The answer to laplacetransform e^{-t}*sin(t) is 1/((s+1)^2+1)

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laplacetransform e^{-t}*sin(t)

laplace transform

e^{- t} \cdot sin (t)

\frac{1}{( s + 1 ) ^{2} + 1}

Solution steps

L {e^{- t} sin (t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{- t} sin (t) : f (t) = sin (t), a = - 1

= L {sin (t)} (s + 1)

L {sin (t)} : \frac{1}{s ^{2} + 1}

= \frac{1}{( s + 1 ) ^{2} + 1}

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What is laplacetransform e^{-t}*sin(t) ?
The answer to laplacetransform e^{-t}*sin(t) is 1/((s+1)^2+1)