What is the solution for y^'=0.05ln((4000)/y)y ?

The solution for y^'=0.05ln((4000)/y)y is y=(4000)/(e^{e^{\frac{-t-c_{1)}{20}}}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=0.05ln((4000)/y)y

y^{^{'}} = 0.05 ln (\frac{4000}{y}) y

y = \frac{4000}{e ^{e^{\frac{- t - c _{1}}{20}}}}

Solution steps

y^{'} (t) = 0.05 ln (\frac{4000}{y}) y

Solve separable ODE:

y = \frac{4000}{e ^{e^{\frac{- t - c _{1}}{20}}}}

y = \frac{4000}{e ^{e^{\frac{- t - c _{1}}{20}}}}

ln (1 + 2 x)

\frac{d}{d x} (6 x^{2} - 6 x - 12)

(ln (x))^{3}

\int \frac{2 t}{1 - 4 t ^{4}} d t

\frac{d x}{d t} = - x

What is the solution for y^'=0.05ln((4000)/y)y ?
The solution for y^'=0.05ln((4000)/y)y is y=(4000)/(e^{e^{\frac{-t-c_{1)}{20}}}}