What is the derivative of ln(x^2+6) ?

The derivative of ln(x^2+6) is (2x)/(x^2+6)

What is the first derivative of ln(x^2+6) ?

The first derivative of ln(x^2+6) is (2x)/(x^2+6)

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derivative of

ln (x^{2} + 6)

\frac{2 x}{x ^{2} + 6}

Solution steps

\frac{d}{d x} (ln (x^{2} + 6))

Apply the chain rule:

\frac{1}{x ^{2} + 6} \frac{d}{d x} (x^{2} + 6)

= \frac{1}{x ^{2} + 6} \frac{d}{d x} (x^{2} + 6)

\frac{d}{d x} (x^{2} + 6) = 2 x

= \frac{1}{x ^{2} + 6} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 6} \cdot 2 x : \frac{2 x}{x ^{2} + 6}

= \frac{2 x}{x ^{2} + 6}

12 x

\int \frac{1}{( x - 2 ) ( x ^{2} + 1 )} d x

\int (4 z + 1)^{2} d z

\frac{d}{d x} (x n x)

\frac{d}{d x} (x^{5} - \frac{10}{9} x^{3} + \frac{5}{21} x)

What is the derivative of ln(x^2+6) ?
The derivative of ln(x^2+6) is (2x)/(x^2+6)
What is the first derivative of ln(x^2+6) ?
The first derivative of ln(x^2+6) is (2x)/(x^2+6)