What is the limit as x approaches-2 of sqrt(4-x^2) ?

The limit as x approaches-2 of sqrt(4-x^2) is 0

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limit as x approaches-2 of sqrt(4-x^2)

x \to - 2 lim (4 - x^{2})

0

Solution steps

x \to - 2 lim (4 - x^{2})

Plug in the value

x = - 2

= 4 - (- 2)^{2}

Simplify

4 - (- 2)^{2} : 0

= 0

\frac{sin ( x ) - 1}{sin ( x ) + 4}

\int \frac{1}{f ( x )} d x

\int 1 - cos (2 t) d t

y = x^{3} - 2 x - 2, at x = 1

- sin (x)

What is the limit as x approaches-2 of sqrt(4-x^2) ?
The limit as x approaches-2 of sqrt(4-x^2) is 0