What is area 1/3 x^{1/2}-x^{3/2},x=0,x= 1/3 ?

The answer to area 1/3 x^{1/2}-x^{3/2},x=0,x= 1/3 is 4/(135*3^{1/2)}

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area 1/3 x^{1/2}-x^{3/2},x=0,x= 1/3

area

\frac{1}{3} x^{\frac{1}{2}} - x^{\frac{3}{2}}, x = 0, x = \frac{1}{3}

\frac{4}{135 \cdot 3 ^{\frac{1}{2}}}

Decimal Notation

0.01710 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{1}{3}} \frac{1}{3} x^{\frac{1}{2}} - x^{\frac{3}{2}} d x

Solve

\int_{0}^{\frac{1}{3}} \frac{1}{3} x^{\frac{1}{2}} - x^{\frac{3}{2}} d x : \frac{4}{135 \cdot 3 ^{\frac{1}{2}}}

The area is:

= \frac{4}{135 \cdot 3 ^{\frac{1}{2}}}

\frac{d ^{2}}{d x ^{2}} (x 9 - x)

x \to 4 - lim (\frac{7}{x - 4})

\frac{\partial}{\partial x} (\frac{6}{x ^{4}})

y^{^{''}} + y = 3 sin (4 x)

f (x) = \frac{( x + 1 ) ( 2 x - 3 )}{2 x + 3}

What is area 1/3 x^{1/2}-x^{3/2},x=0,x= 1/3 ?
The answer to area 1/3 x^{1/2}-x^{3/2},x=0,x= 1/3 is 4/(135*3^{1/2)}