What is area y=3-x,y=2x^2,[0,3] ?

The answer to area y=3-x,y=2x^2,[0,3] is 103/6

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area y=3-x,y=2x^2,[0,3]

area

y = 3 - x, y = 2 x^{2}, [0, 3]

\frac{103}{6}

Decimal Notation

17.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{3} 3 - x - 2 x^{2} d x

Solve

\int_{0}^{3} 3 - x - 2 x^{2} d x : \frac{103}{6}

The area is:

= \frac{103}{6}

\frac{d}{d x} (4 x + 2 y)

\frac{\partial}{\partial x} (- 6 x^{3} + y^{2} + 5 x y)

\frac{- 2 x}{( x ^{2} + 1 ) ^{2}}

\frac{1}{x} + e^{x}

x \to - 6 lim (\frac{x + 9}{x + 6})

What is area y=3-x,y=2x^2,[0,3] ?
The answer to area y=3-x,y=2x^2,[0,3] is 103/6