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Popular >

xy^'+y+y^2=0,y(1)=2

Solution

x y^{^{'}} + y + y^{2} = 0, y (1) = 2

Solution

y = - \frac{2}{2 - 3 x}

Solution steps

x y^{'} (x) + y + y^{2} = 0

Solve separable ODE:

y = - \frac{2}{2 - 3 x}

y = - \frac{2}{2 - 3 x}

Popular Examples

(\partial)/(\partial x)(1/2 xy^2)

\frac{\partial}{\partial x} (\frac{1}{2} x y^{2})

limit as x approaches 0 of (10^x-e^x)/x

x \to 0 lim (\frac{1 0 ^{x} - e ^{x}}{x})

limit as x approaches-infinity of x/3

x \to - \infty lim (\frac{x}{3})

lcm f(x)=,sqrt(x)lcm

f (x) =, x

derivative of 15-x^2

\frac{d}{d x} (15 - x^{2})

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y+y^2=0,y(1)=2 ?
The solution for xy^'+y+y^2=0,y(1)=2 is y=-2/(2-3x)