What is the derivative of f(x)=x^2-8 ?

The derivative of f(x)=x^2-8 is 2x

What is the first derivative of f(x)=x^2-8 ?

The first derivative of f(x)=x^2-8 is 2x

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derivative of

f (x) = x^{2} - 8

2 x

Solution steps

\frac{d}{d x} (x^{2} - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8) = 0

= 2 x - 0

Simplify

= 2 x

\frac{s + 1}{s ^{2} ( s + 2 ) ^{3}}

\int 5 t d t

7 sin (\frac{3}{2} t)

y^{^{''}} - y^{^{'}} + 5 y = 0

t e^{- 2 t}

What is the derivative of f(x)=x^2-8 ?
The derivative of f(x)=x^2-8 is 2x
What is the first derivative of f(x)=x^2-8 ?
The first derivative of f(x)=x^2-8 is 2x