What is the integral from 1 to 3 of 2^x ?

The integral from 1 to 3 of 2^x is 6/(ln(2))

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integral from 1 to 3 of 2^x

\int_{1}^{3} 2^{x} d x

\frac{6}{ln ( 2 )}

Decimal Notation

8.65617 \dots

Solution steps

\int_{1}^{3} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{1}^{3}

Compute the boundaries:

\frac{6}{ln ( 2 )}

= \frac{6}{ln ( 2 )}

f (x) = x^{2} + 36

\int \frac{1}{x - 70} d x

\int \frac{9 x ^{2} - 8 x + 4}{x ^{3} + 4 x} d x

\frac{\partial}{\partial x} (6 x^{4} y - 3 x y + 2 y)

x \to 2 lim (3 - x)

What is the integral from 1 to 3 of 2^x ?
The integral from 1 to 3 of 2^x is 6/(ln(2))