What is the solution for 1/(x^8)y^'=12+15y ?

The solution for 1/(x^8)y^'=12+15y is y=(e^{(5x^9+c_{1})/3})/(5)-4/5

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1/(x^8)y^'=12+15y

\frac{1}{x ^{8}} y^{^{'}} = 12 + 15 y

y = \frac{e ^{\frac{5 x ^{9} + c _{1}}{3}}}{5} - \frac{4}{5}

Solution steps

\frac{1}{x ^{8}} y^{'} (x) = 12 + 15 y

Solve separable ODE:

y = \frac{e ^{\frac{5 x ^{9} + c _{1}}{3}}}{5} - \frac{4}{5}

y = \frac{e ^{\frac{5 x ^{9} + c _{1}}{3}}}{5} - \frac{4}{5}

\frac{\partial}{\partial x} (x^{2} y + x y^{2})

y = x^{3}, at x = - 9

(1 + sin (x))^{- 4}

\int (\frac{1}{x} + \frac{1}{3 - x}) d x

x \to 0 lim (sin (5 x) csc (3 x))

What is the solution for 1/(x^8)y^'=12+15y ?
The solution for 1/(x^8)y^'=12+15y is y=(e^{(5x^9+c_{1})/3})/(5)-4/5