What is the limit as x approaches-2+of (x+1)/(x+2) ?

The limit as x approaches-2+of (x+1)/(x+2) is -infinity

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limit as x approaches-2+of (x+1)/(x+2)

x \to - 2 + lim (\frac{x + 1}{x + 2})

- \infty

Solution steps

x \to - 2 + lim (\frac{x + 1}{x + 2})

\frac{x + 1}{x + 2} = (x + 1) \frac{1}{x + 2}

= x \to - 2 + lim ((x + 1) \frac{1}{x + 2})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 2 + lim (x + 1) \cdot x \to - 2 + lim (\frac{1}{x + 2})

x \to - 2 + lim (x + 1) = - 1

x \to - 2 + lim (\frac{1}{x + 2}) = \infty

= (- 1) \cdot \infty

Apply Infinity Property:

- c \cdot \infty = - \infty

= - \infty

\int \frac{1}{x 4 x ^{2} - 16} d x

y = 7 + 5 x^{2} - 2 x^{3}, (2, 11)

x \to 2 lim (\frac{x + 4}{x - 2})

\frac{d}{d x} (ln (cos (\frac{1}{x})))

\frac{d y}{d x} = e^{5 x} + 8 y

What is the limit as x approaches-2+of (x+1)/(x+2) ?
The limit as x approaches-2+of (x+1)/(x+2) is -infinity